时间复杂度:(O)n

#include<iostream> using namespace std; int main(){ int a,s; cin>>a>>s; int d = a*2; int z = 0,x = 0,c = 0; if(s>=d){ int z = s-d; int x = z/2; int c = a-x; cout<<c<<" "<<x; } return 0; }