题解-鸡兔同笼

#include<iostream>
using namespace std;
int main(){
    int mltt=0,kunkun,head,jio;
    cin>>head>>jio;
    kunkun=head;
    for(int i=1;i<=head;i++){
        if(mltt*4+kunkun*2==jio){
            cout<<kunkun<<" "<<mltt;
            break;
        }else{
            mltt=mltt+1;
            kunkun=kunkun-1;
        }
    }
    return 0;
}

时间复杂度:(O)n