o(1)解法

#include<iostream>
using namespace std;
int n,m;
int main(){
    cin>>n>>m;
    int extfoot=n*4-m;
    int chik=extfoot/2;
    int rabb=n-chik;
    cout<<chik<<' '<<rabb;
}



事实上就是数学  [:ACGO_再见]