CF1850A.To My Critics

Suneet has three digits $a$, $b$, and $c$.

Since math isn't his strongest point, he asks you to determine if you can choose any two digits to make a sum greater or equal to $10$.

Output "YES" if there is such a pair, and "NO" otherwise.

苏尼特有三个数字 $a$、$b$ 和 $c$。

由于数学不是他的强项，他请你判断：是否能从中任选两个数字，使其和大于或等于 $10$。

若存在这样的一对数字，输出 "YES"；否则输出 "NO"。

The first line contains a single integer $t$ ($1 \leq t \leq 1000$) — the number of test cases.

The only line of each test case contains three digits $a$, $b$, $c$ ($0 \leq a, b, c \leq 9$).

第一行包含一个整数 $t$（$1 \leq t \leq 1000$）—— 表示测试用例的数量。

每个测试用例仅有一行，包含三个数字 $a$、$b$、$c$（$0 \leq a, b, c \leq 9$）。

For each test case, output "YES" if such a pair exists, and "NO" otherwise.

You can output the answer in any case (for example, the strings "yEs", "yes", "Yes" and "YES" will be recognized as a positive answer).

对于每个测试用例，如果存在这样的一对数，则输出 “YES”，否则输出 “NO”。

您可以以任意大小写形式输出答案（例如，字符串 “yEs”、“yes”、“Yes” 和 “YES” 均会被识别为肯定回答）。

For the first test case, by choosing the digits $8$ and $2$ we can obtain a sum of $8 + 2 = 10$ which satisfies the condition, thus the output should be "YES".

For the second test case, any combination of chosen digits won't be at least $10$, thus the output should be "NO" (note that we can not choose the digit on the same position twice).

For the third test case, any combination of chosen digits will have a sum equal to $18$, thus the output should be "YES".

对于第一个测试用例，通过选择数字 $8$ 和 $2$，我们可以得到和为 $8 + 2 = 10$，满足条件，因此输出应为 "YES"。

对于第二个测试用例，任意选择的数字组合之和均无法达到至少 $10$，因此输出应为 "NO"（注意：我们不能两次选择同一位置上的数字）。

对于第三个测试用例，任意选择的数字组合之和均为 $18$，因此输出应为 "YES"。