CF1738H.Palindrome Addicts
NOI/NOI+/CTSC
通过率:0%
时间限制:2.00s
内存限制:1024MB
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题目描述
Your task is to maintain a queue consisting of lowercase English letters as follows:
- "push c": insert a letter c at the back of the queue;
- "pop": delete a letter from the front of the queue.
Initially, the queue is empty.
After each operation, you are asked to count the number of distinct palindromic substrings in the string that are obtained by concatenating the letters from the front to the back of the queue.
Especially, the number of distinct palindromic substrings of the empty string is 0.
A string s[1..n] of length n is palindromic if s[i]=s[n−i+1] for every 1≤i≤n.
The string s[l..r] is a substring of string s[1..n] for every 1≤l≤r≤n.
Two strings s[1..n] and t[1..m] are distinct, if at least one of the following holds.
- n=m;
- s[i]=t[i] for some 1≤i≤minn,m.
你的任务是维护一个由小写英文字母组成的队列,具体操作如下:
- “push c”:将字母 c 插入队列尾部;
- “pop”:从队列头部删除一个字母。
初始时,队列为空。
每次操作后,你需要计算当前队列中从头到尾拼接所得字符串中不同的回文子串的个数。
特别地,空字符串的不同回文子串个数为 0。
长度为 n 的字符串 s[1..n] 是回文串,当且仅当对所有 1≤i≤n,均有 s[i]=s[n−i+1]。
对任意满足 1≤l≤r≤n 的整数 l,r,字符串 s[l..r] 是字符串 s[1..n] 的一个子串。
两个字符串 s[1..n] 与 t[1..m] 被称为不同,当且仅当以下任一条件成立:
- n=m;
- 存在某个 1≤i≤min{n,m},使得 s[i]=t[i]。
输入格式
The first line is an integer q (1≤q≤106), indicating the number of operations.
Then q lines follow. Each of the following lines contains one of the operations as follows.
- "push c": insert a letter c at the back of the queue, where c is a lowercase English letter;
- "pop": delete a letter from the front of the queue.
It is guaranteed that no "pop" operation will be performed when the queue is empty.
第一行是一个整数 q(1≤q≤106),表示操作的次数。
接下来有 q 行,每行包含以下操作之一:
- “push c”:将小写字母 c 插入队列尾部;
- “pop”:从队列头部删除一个字母。
保证不会在队列为空时执行 “pop” 操作。
输出格式
After each operation, print the number of distinct palindromic substrings in the string presented in the queue.
每次操作后,输出队列中字符串的不同回文子串的数量。
输入输出样例
输入#1
12 push a pop push a push a push b push b push a push a pop pop pop push b
输出#1
1 0 1 2 3 4 5 6 5 4 3 4
说明/提示
Let sk be the string presented in the queue after the k-th operation, and let ck be the number of distinct palindromic substrings of sk. The following table shows the details of the example.
k
sk
ck
1
a
1
2
empty
0
3
a
1
4
aa
2
5
aab
3
6
aabb
4
7
aabba
5
8
aabbaa
6
9
abbaa
5
10
bbaa
4
11
baa
3
12
baab
4
It is worth pointing out that
- After the 2-nd operation, the string is empty and thus has no substrings. So the answer is 0;
- After the 8-th operation, the string is "aabbaa". The 6 distinct palindromic substrings are "a", "aa", "aabbaa", "abba", "b", and "bb".
令 sk 表示第 k 次操作后队列中呈现的字符串,ck 表示 sk 中不同回文子串的个数。下表展示了该示例的详细信息。
k
sk
ck
1
a
1
2
empty
0
3
a
1
4
aa
2
5
aab
3
6
aabb
4
7
aabba
5
8
aabbaa
6
9
abbaa
5
10
bbaa
4
11
baa
3
12
baab
4
需要特别指出的是:
- 第 2 次操作后,字符串为空,因此没有子串,答案为 0;
- 第 8 次操作后,字符串为 "aabbaa"。其 6 个不同的回文子串为 "a"、"aa"、"aabbaa"、"abba"、"b" 和 "bb"。
输入解题思路,AI测评打分。不知道怎么写?