CF1714G.Path Prefixes

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题目描述

You are given a rooted tree. It contains nn vertices, which are numbered from 11 to nn . The root is the vertex 11 .

Each edge has two positive integer values. Thus, two positive integers aja_j and bjb_j are given for each edge.

Output n1n-1 numbers r2,r3,,rnr_2, r_3, \dots, r_n , where rir_i is defined as follows.

Consider the path from the root (vertex 11 ) to ii ( 2in2 \le i \le n ). Let the sum of the costs of aja_j along this path be AiA_i . Then rir_i is equal to the length of the maximum prefix of this path such that the sum of bjb_j along this prefix does not exceed AiA_i .

Example for n=9n=9 . The blue color shows the costs of aja_j , and the red color shows the costs of bjb_j .Consider an example. In this case:

  • r2=0r_2=0 , since the path to 22 has an amount of aja_j equal to 55 , only the prefix of this path of length 00 has a smaller or equal amount of bjb_j ;
  • r3=3r_3=3 , since the path to 33 has an amount of aja_j equal to 5+9+5=195+9+5=19 , the prefix of length 33 of this path has a sum of bjb_j equal to 6+10+1=176+10+1=17 ( the number is 171917 \le 19 );
  • r4=1r_4=1 , since the path to 44 has an amount of aja_j equal to 5+9=145+9=14 , the prefix of length 11 of this path has an amount of bjb_j equal to 66 (this is the longest suitable prefix, since the prefix of length 22 already has an amount of bjb_j equal to 6+10=166+10=16 , which is more than 1414 );
  • r5=2r_5=2 , since the path to 55 has an amount of aja_j equal to 5+9+2=165+9+2=16 , the prefix of length 22 of this path has a sum of bjb_j equal to 6+10=166+10=16 (this is the longest suitable prefix, since the prefix of length 33 already has an amount of bjb_j equal to 6+10+1=176+10+1=17 , what is more than 1616 );
  • r6=1r_6=1 , since the path up to 66 has an amount of aja_j equal to 22 , the prefix of length 11 of this path has an amount of bjb_j equal to 11 ;
  • r7=1r_7=1 , since the path to 77 has an amount of aja_j equal to 5+3=85+3=8 , the prefix of length 11 of this path has an amount of bjb_j equal to 66 (this is the longest suitable prefix, since the prefix of length 22 already has an amount of bjb_j equal to 6+3=96+3=9 , which is more than 88 );
  • r8=2r_8=2 , since the path up to 88 has an amount of aja_j equal to 2+4=62+4=6 , the prefix of length 22 of this path has an amount of bjb_j equal to 1+3=41+3=4 ;
  • r9=3r_9=3 , since the path to 99 has an amount of aja_j equal to 2+4+1=72+4+1=7 , the prefix of length 33 of this path has a sum of bjb_j equal to 1+3+3=71+3+3=7 .

输入格式

The first line contains an integer tt ( 1t1041 \le t \le 10^4 ) — the number of test cases in the test.

The descriptions of test cases follow.

Each description begins with a line that contains an integer nn ( 2n21052 \le n \le 2\cdot10^5 ) — the number of vertices in the tree.

This is followed by n1n-1 string, each of which contains three numbers pj,aj,bjp_j, a_j, b_j ( 1pjn1 \le p_j \le n ; 1aj,bj1091 \le a_j,b_j \le 10^9 ) — the ancestor of the vertex jj , the first and second values an edge that leads from pjp_j to jj . The value of jj runs through all values from 22 to nn inclusive. It is guaranteed that each set of input data has a correct hanged tree with a root at the vertex 11 .

It is guaranteed that the sum of nn over all input test cases does not exceed 21052\cdot10^5 .

输出格式

For each test case, output n1n-1 integer in one line: r2,r3,,rnr_2, r_3, \dots, r_n .

输入输出样例

  • 输入#1

    4
    9
    1 5 6
    4 5 1
    2 9 10
    4 2 1
    1 2 1
    2 3 3
    6 4 3
    8 1 3
    4
    1 1 100
    2 1 1
    3 101 1
    4
    1 100 1
    2 1 1
    3 1 101
    10
    1 1 4
    2 3 5
    2 5 1
    3 4 3
    3 1 5
    5 3 5
    5 2 1
    1 3 2
    6 2 1

    输出#1

    0 3 1 2 1 1 2 3 
    0 0 3 
    1 2 2 
    0 1 2 1 1 2 2 1 1

说明/提示

The first example is clarified in the statement.

In the second example:

  • r2=0r_2=0 , since the path to 22 has an amount of aja_j equal to 11 , only the prefix of this path of length 00 has a smaller or equal amount of bjb_j ;
  • r3=0r_3=0 , since the path to 33 has an amount of aja_j equal to 1+1=21+1=2 , the prefix of length 11 of this path has an amount of bjb_j equal to 100100 ( 100>2100 > 2 );
  • r4=3r_4=3 , since the path to 44 has an amount of aja_j equal to 1+1+101=1031+1+101=103 , the prefix of length 33 of this path has an amount of bjb_j equal to 102102 , .
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