CF1635F.Closest Pair
省选/NOI-
通过率:0%
时间限制:3.00s
内存限制:256MB
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题目描述
There are n weighted points on the OX-axis. The coordinate and the weight of the i-th point is xi and wi, respectively. All points have distinct coordinates and positive weights. Also, xi<xi+1 holds for any 1≤i<n.
The weighted distance between i-th point and j-th point is defined as ∣xi−xj∣⋅(wi+wj), where ∣val∣ denotes the absolute value of val.
You should answer q queries, where the i-th query asks the following: Find the minimum weighted distance among all pairs of distinct points among the points in subarray [li,ri].
在 OX 轴上有 n 个带权点。第 i 个点的坐标和权重分别为 xi 和 wi。所有点的坐标互不相同,且权重均为正数;此外,对任意 1≤i<n,均满足 xi<xi+1。
第 i 个点与第 j 个点之间的加权距离定义为 ∣xi−xj∣⋅(wi+wj),其中 ∣val∣ 表示 val 的绝对值。
你需要回答 q 个查询,其中第 i 个查询要求:在子数组 [li,ri] 所包含的点中,求所有不同点对之间的最小加权距离。
输入格式
The first line contains 2 integers n and q (2≤n≤3⋅105;1≤q≤3⋅105) — the number of points and the number of queries.
Then, n lines follows, the i-th of them contains two integers xi and wi (−109≤xi≤109;1≤wi≤109) — the coordinate and the weight of the i-th point.
It is guaranteed that the points are given in the increasing order of x.
Then, q lines follows, the i-th of them contains two integers li and ri (1≤li<ri≤n) — the given subarray of the i-th query.
第一行包含两个整数 n 和 q(2≤n≤3⋅105;1≤q≤3⋅105)—— 分别表示点的数量和查询的数量。
接下来是 n 行,其中第 i 行包含两个整数 xi 和 wi(−109≤xi≤109;1≤wi≤109)—— 分别表示第 i 个点的坐标和权重。
保证输入的点按 x 坐标严格递增给出。
接下来是 q 行,其中第 i 行包含两个整数 li 和 ri(1≤li<ri≤n)—— 表示第 i 次查询所给定的子数组范围。
输出格式
For each query output one integer, the minimum weighted distance among all pair of distinct points in the given subarray.
对于每个查询,输出一个整数,表示给定子数组中所有不同点对的最小加权距离。
输入输出样例
输入#1
5 5 -2 2 0 10 1 1 9 2 12 7 1 3 2 3 1 5 3 5 2 4
输出#1
9 11 9 24 11
说明/提示
For the first query, the minimum weighted distance is between points 1 and 3, which is equal to ∣x1−x3∣⋅(w1+w3)=∣−2−1∣⋅(2+1)=9.
For the second query, the minimum weighted distance is between points 2 and 3, which is equal to ∣x2−x3∣⋅(w2+w3)=∣0−1∣⋅(10+1)=11.
For the fourth query, the minimum weighted distance is between points 3 and 4, which is equal to ∣x3−x4∣⋅(w3+w4)=∣1−9∣⋅(1+2)=24.
对于第一个查询,最小加权距离出现在点 1 和点 3 之间,其值为 ∣x1−x3∣⋅(w1+w3)=∣−2−1∣⋅(2+1)=9。
对于第二个查询,最小加权距离出现在点 2 和点 3 之间,其值为 ∣x2−x3∣⋅(w2+w3)=∣0−1∣⋅(10+1)=11。
对于第四个查询,最小加权距离出现在点 3 和点 4 之间,其值为 ∣x3−x4∣⋅(w3+w4)=∣1−9∣⋅(1+2)=24。
输入解题思路,AI测评打分。不知道怎么写?