CF1389G.Directing Edges

省选/NOI-

通过率:0%

时间限制:4.00s

内存限制:512MB

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

You are given an undirected connected graph consisting of nn vertices and mm edges. kk vertices of this graph are special.

You have to direct each edge of this graph or leave it undirected. If you leave the ii-th edge undirected, you pay wiw_i coins, and if you direct it, you don't have to pay for it.

Let's call a vertex saturated if it is reachable from each special vertex along the edges of the graph (if an edge is undirected, it can be traversed in both directions). After you direct the edges of the graph (possibly leaving some of them undirected), you receive cic_i coins for each saturated vertex ii. Thus, your total profit can be calculated as ∑i∈Sci−∑j∈Uwj\sum \limits_{i \in S} c_i - \sum \limits_{j \in U} w_j, where SS is the set of saturated vertices, and UU is the set of edges you leave undirected.

For each vertex ii, calculate the maximum possible profit you can get if you have to make the vertex ii saturated.

你被给定一个包含 nn 个顶点和 mm 条边的无向连通图。该图中有 kk 个顶点是特殊的。

你需要为图中的每条边指定一个方向,或保持其无向。若将第 ii 条边保持无向,则需支付 wiw_i 枚金币;若为其指定方向,则无需为此边付费。

我们称一个顶点是饱和的(saturated),当且仅当它可以从每个特殊顶点出发,沿着图中的边(若某边保持无向,则可双向通行)到达。在你为图的边定向(可能保留其中一些边为无向)之后,对每个饱和顶点 ii,你将获得 cic_i 枚金币。因此,你的总收益可计算为 ∑i∈Sci−∑j∈Uwj\sum \limits_{i \in S} c_i - \sum \limits_{j \in U} w_j,其中 SS 是饱和顶点的集合,UU 是你保留为无向的边的集合。

对每个顶点 ii,请计算:在强制要求顶点 ii 必须为饱和顶点的前提下,你能获得的最大可能收益。

输入格式

The first line contains three integers nn, mm and kk (2≤n≤3⋅1052 \le n \le 3 \cdot 10^5, n−1≤m≤min⁡(3⋅105,n(n−1)2)n - 1 \le m \le \min(3 \cdot 10^5, \frac{n(n-1)}{2}), 1≤k≤n1 \le k \le n).

The second line contains kk pairwise distinct integers v1v_1, v2v_2, ..., vkv_k (1≤vi≤n1 \le v_i \le n) — the indices of the special vertices.

The third line contains nn integers c1c_1, c2c_2, ..., cnc_n (0≤ci≤1090 \le c_i \le 10^9).

The fourth line contains mm integers w1w_1, w2w_2, ..., wmw_m (0≤wi≤1090 \le w_i \le 10^9).

Then mm lines follow, the ii-th line contains two integers xix_i and yiy_i (1≤xi,yi≤n1 \le x_i, y_i \le n, xi≠yix_i \ne y_i) — the endpoints of the ii-th edge.

There is at most one edge between each pair of vertices.

第一行包含三个整数 nn、mm 和 kk(2≤n≤3⋅1052 \le n \le 3 \cdot 10^5,n−1≤m≤min⁡(3⋅105,n(n−1)2)n - 1 \le m \le \min(3 \cdot 10^5, \frac{n(n-1)}{2}),1≤k≤n1 \le k \le n)。

第二行包含 kk 个两两不同的整数 v1v_1、v2v_2、…、vkv_k(1≤vi≤n1 \le v_i \le n)—— 特殊顶点的编号。

第三行包含 nn 个整数 c1c_1、c2c_2、…、cnc_n(0≤ci≤1090 \le c_i \le 10^9)。

第四行包含 mm 个整数 w1w_1、w2w_2、…、wmw_m(0≤wi≤1090 \le w_i \le 10^9)。

接下来是 mm 行,其中第 ii 行包含两个整数 xix_i 和 yiy_i(1≤xi,yi≤n1 \le x_i, y_i \le n,xi≠yix_i \ne y_i)—— 第 ii 条边的两个端点。

任意一对顶点之间至多存在一条边。

输出格式

Print nn integers, where the ii-th integer is the maximum profit you can get if you have to make the vertex ii saturated.

输出 nn 个整数,其中第 ii 个整数表示:若必须使顶点 ii 达到饱和状态,你能获得的最大利润。

输入输出样例

  • 输入#1

    3 2 2
    1 3
    11 1 5
    10 10
    1 2
    2 3

    输出#1

    11 2 5
  • 输入#2

    4 4 4
    1 2 3 4
    1 5 7 8
    100 100 100 100
    1 2
    2 3
    3 4
    1 4

    输出#2

    21 21 21 21

说明/提示

Consider the first example:

  • the best way to make vertex 11 saturated is to direct the edges as 2→12 \to 1, 3→23 \to 2; 11 is the only saturated vertex, so the answer is 1111;
  • the best way to make vertex 22 saturated is to leave the edge 1−21-2 undirected and direct the other edge as 3→23 \to 2; 11 and 22 are the saturated vertices, and the cost to leave the edge 1−21-2 undirected is 1010, so the answer is 22;
  • the best way to make vertex 33 saturated is to direct the edges as 2→32 \to 3, 1→21 \to 2; 33 is the only saturated vertex, so the answer is 55.

The best course of action in the second example is to direct the edges along the cycle: 1→21 \to 2, 2→32 \to 3, 3→43 \to 4 and 4→14 \to 1. That way, all vertices are saturated.

考虑第一个例子:

  • 使顶点 11 达到饱和的最优方式是将边定向为 2→12 \to 1、3→23 \to 2;此时仅顶点 11 是饱和的,因此答案为 1111;
  • 使顶点 22 达到饱和的最优方式是保持边 1-21\text{-}2 无向,并将另一条边定向为 3→23 \to 2;此时顶点 11 和 22 均为饱和顶点,而保持边 1-21\text{-}2 无向的代价为 1010,因此答案为 22;
  • 使顶点 33 达到饱和的最优方式是将边定向为 2→32 \to 3、1→21 \to 2;此时仅顶点 33 是饱和的,因此答案为 55。

第二个例子中的最优策略是沿环定向各条边:1→21 \to 2、2→32 \to 3、3→43 \to 4 和 4→14 \to 1。这样,所有顶点均达到饱和。

输入解题思路,AI测评打分。不知道怎么写?

首页