CF811B.Vladik and Complicated Book
普及-
通过率:0%
时间限制:2.00s
内存限制:256MB
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题目描述
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [_p_1, _p_2, ..., p__n], where p__i denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has p__x changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
弗拉迪克开始阅读一本关于算法的复杂书籍,该书共有 n 页。为了加深对书中内容的理解,他的朋友们建议他按照某个由排列 P=[p1,p2,…,pn] 给出的顺序来阅读,其中 pi 表示第 i 个应被阅读的页码。
有时,弗拉迪克的妈妈会将排列 P 中从位置 l 到位置 r(包含端点)的某个子段进行升序排序,因为她喜欢有序。对于每一次这样的排序操作,弗拉迪克都知道一个数 x —— 即他在排序后应当阅读的页码在排列中的索引(即排序后他要读的是第 x 个位置上的页码)。他很好奇:经过此次排序后,他将要阅读的页码是否发生了变化?换言之,px 的值是否发生了改变?每次排序结束后,弗拉迪克都会将排列恢复为初始状态,因此你可以认为每次排序操作都是相互独立的。
输入格式
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers _p_1, _p_2, ..., p__n (1 ≤ p__i ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers l__i, r__i, x__i (1 ≤ l__i ≤ x__i ≤ r__i ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
第一行包含两个用空格分隔的整数 n、m(1≤n,m≤104)—— 分别表示排列的长度以及弗拉迪克(Vladik)妈妈对书中某子段进行排序的次数。
第二行包含 n 个用空格分隔的整数 p1,p2,…,pn(1≤pi≤n)—— 排列 P。注意:排列中的元素互不相同。
接下来的 m 行中,每行包含三个用空格分隔的整数 li,ri,xi(1≤li≤xi≤ri≤n)—— 分别表示第 i 次排序操作所作用子段的左右边界,以及弗拉迪克感兴趣的下标位置。
输出格式
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
对于每位母亲的排序,若 Vladik 感兴趣的页面未发生变化,则在单独一行输出“Yes”;否则输出“No”。
输入输出样例
输入#1
5 5 5 4 3 2 1 1 5 3 1 3 1 2 4 3 4 4 4 2 5 3
输出#1
Yes No Yes Yes No
输入#2
6 5 1 4 3 2 5 6 2 4 3 1 6 2 4 5 4 1 3 3 2 6 3
输出#2
Yes No Yes No Yes
说明/提示
Explanation of first test case:
- [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
- [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
- [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
- [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
- [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
第一个测试用例的解释:
- [1, 2, 3, 4, 5] — 排序后的排列,第 3 个元素未发生变化,因此答案为 “Yes”。
- [3, 4, 5, 2, 1] — 排序后的排列,第 1 个元素已发生变化,因此答案为 “No”。
- [5, 2, 3, 4, 1] — 排序后的排列,第 3 个元素未发生变化,因此答案为 “Yes”。
- [5, 4, 3, 2, 1] — 排序后的排列,第 4 个元素未发生变化,因此答案为 “Yes”。
- [5, 1, 2, 3, 4] — 排序后的排列,第 3 个元素已发生变化,因此答案为 “No”。
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