CF746A.Compote

Nikolay has a lemons, b apples and c pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1: 2: 4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — lemons, apples and pears — should be put in the compote as whole fruits.

Your task is to determine the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. It is possible that Nikolay can't use any fruits, in this case print 0.

尼古拉有 $a$ 个柠檬、$b$ 个苹果和 $c$ 个梨。他决定制作一道果酱（compote）。根据食谱，这三种水果的数量比例应为 $1:2:4$，即：每放入 1 个柠檬，就必须恰好放入 2 个苹果和 4 个梨。你不可以将这些水果捣碎、掰开或切块；柠檬、苹果和梨都必须以完整果实的形式加入果酱中。

你的任务是确定尼古拉最多能用多少个柠檬、苹果和梨来制作果酱（即三者总数的最大值）。有可能尼古拉一个水果都无法使用，此时请输出 0。

The first line contains the positive integer a (1 ≤ a ≤ 1000) — the number of lemons Nikolay has.

The second line contains the positive integer b (1 ≤ b ≤ 1000) — the number of apples Nikolay has.

The third line contains the positive integer c (1 ≤ c ≤ 1000) — the number of pears Nikolay has.

第一行包含一个正整数 $a$（$1 \le a \le 1000$）—— Nikolay 拥有的柠檬数量。

第二行包含一个正整数 $b$（$1 \le b \le 1000$）—— Nikolay 拥有的苹果数量。

第三行包含一个正整数 $c$（$1 \le c \le 1000$）—— Nikolay 拥有的梨数量。

Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote.

输出尼古拉可以用来制作蜜饯的柠檬、苹果和梨的最大总数。

In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.

In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.

In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0.

在第一个例子中，尼古拉可以使用 1 个柠檬、2 个苹果和 4 个梨，因此答案为 $1 + 2 + 4 = 7$。

在第二个例子中，尼古拉可以使用 3 个柠檬、6 个苹果和 12 个梨，因此答案为 $3 + 6 + 12 = 21$。

在第三个例子中，尼古拉没有足够的梨来制作任何什锦水果羹，因此答案为 $0$。