CF630A.Again Twenty Five!

The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the number. Yes, of course, n can be rather big, and one cannot find the power using a calculator, but we need people who are able to think, not just follow the instructions."

Could you pass the interview in the machine vision company in IT City?

人力资源经理再次失望了。最后一位应聘者与此前24位一样，面试失败。“我出的题真的这么难吗？”人力资源经理心想，“只要将数字5的 n 次方求出来，再取结果的最后两位数字即可。没错，当然，n 可能非常大，无法用计算器直接计算幂，但我们需要的是善于思考的人，而不是只会按指令行事的人。”

你能在IT城的一家机器视觉公司通过这场面试吗？

The only line of the input contains a single integer n (2 ≤ n ≤ 2·1018) — the power in which you need to raise number 5.

输入仅包含一行，其中有一个整数 $ n $（$ 2 \leq n \leq 2 \cdot 10^{18} $）——即你需要将数字 5 提升到的幂次。

Output the last two digits of 5_n_ without spaces between them.

输出 $5_n$ 的最后两位数字，中间不加空格。