CF579A.Raising Bacteria

You are a lover of bacteria. You want to raise some bacteria in a box.

Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly x bacteria in the box at some moment.

What is the minimum number of bacteria you need to put into the box across those days?

你是一位细菌爱好者，想要在一个盒子里培养一些细菌。

初始时，盒子是空的。每天早上，你可以向盒子中放入任意数量的细菌；而每天晚上，盒子里的每个细菌都会分裂成两个细菌。你希望在某一时刻，盒子里恰好有 $x$ 个细菌。

请问：在整个过程中，你需要放入盒子的细菌总数的最小值是多少？

The only line containing one integer x (1 ≤ x ≤ 109).

仅有一行，包含一个整数 $x$（$1 \leq x \leq 10^9$）。

The only line containing one integer: the answer.

仅包含一个整数的一行：答案。

For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.

For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1.

对于第一个样例，我们可以在第一天早晨向盒中添加一个细菌，到第三天早晨时盒中将有 4 个细菌。此时我们再放入一个细菌，使盒中细菌总数变为 5。整个过程中我们共添加了 2 个细菌，因此答案为 2。

对于第二个样例，我们可以在第一天早晨放入一个细菌，到第四天早晨时盒中将有 8 个细菌。因此答案为 1。