CF556B.Case of Fake Numbers
普及-
通过率:0%
时间限制:2.00s
内存限制:256MB
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题目描述
Andrewid the Android is a galaxy-famous detective. He is now investigating a case of frauds who make fake copies of the famous Stolp's gears, puzzles that are as famous as the Rubik's cube once was.
Its most important components are a button and a line of n similar gears. Each gear has n teeth containing all numbers from 0 to n - 1 in the counter-clockwise order. When you push a button, the first gear rotates clockwise, then the second gear rotates counter-clockwise, the the third gear rotates clockwise an so on.
Besides, each gear has exactly one active tooth. When a gear turns, a new active tooth is the one following after the current active tooth according to the direction of the rotation. For example, if n = 5, and the active tooth is the one containing number 0, then clockwise rotation makes the tooth with number 1 active, or the counter-clockwise rotating makes the tooth number 4 active.
Andrewid remembers that the real puzzle has the following property: you can push the button multiple times in such a way that in the end the numbers on the active teeth of the gears from first to last form sequence 0, 1, 2, ..., n - 1. Write a program that determines whether the given puzzle is real or fake.
安卓侦探安德鲁伊德是银河系闻名的侦探。他目前正在调查一起造假案,涉案人员制造了著名斯托尔普齿轮谜题(Stolp's gears)的仿冒品——这种谜题的知名度曾堪比魔方。
该谜题最重要的组成部分是一个按钮和一排 n 个完全相同的齿轮。每个齿轮有 n 个齿,按逆时针顺序依次标有数字 0 到 n−1。当你按下按钮时,第一个齿轮顺时针旋转,第二个齿轮逆时针旋转,第三个齿轮顺时针旋转,依此类推。
此外,每个齿轮恰好有一个“激活齿”(active tooth)。当齿轮转动时,新的激活齿即为当前激活齿沿旋转方向的下一个齿。例如,若 n=5,当前激活齿标号为 0,则顺时针旋转会使标号为 1 的齿变为激活齿,而逆时针旋转则会使标号为 4 的齿变为激活齿。
安德鲁伊德记得,真正的谜题具有如下性质:存在某种按按钮的次数(可多次),使得最终从第一个齿轮到第 n 个齿轮的激活齿上的数字依次构成序列 0,1,2,…,n−1。请编写一个程序,判断给定的谜题是真品还是赝品。
输入格式
The first line contains integer n (1 ≤ n ≤ 1000) — the number of gears.
The second line contains n digits _a_1, _a_2, ..., a__n (0 ≤ a__i ≤ n - 1) — the sequence of active teeth: the active tooth of the i-th gear contains number a__i.
第一行包含一个整数 n(1≤n≤1000)——齿轮的数量。
第二行包含 n 个数字 a1,a2,…,an(0≤ai≤n−1)——活跃齿的序列:第 i 个齿轮的活跃齿上标有数字 ai。
输出格式
In a single line print "Yes" (without the quotes), if the given Stolp's gears puzzle is real, and "No" (without the quotes) otherwise.
如果给定的斯托尔普齿轮谜题是真实的,则在一行中输出“Yes”(不带引号);否则输出“No”(不带引号)。
输入输出样例
输入#1
3 1 0 0
输出#1
Yes
输入#2
5 4 2 1 4 3
输出#2
Yes
输入#3
4 0 2 3 1
输出#3
No
说明/提示
In the first sample test when you push the button for the first time, the sequence of active teeth will be 2 2 1, when you push it for the second time, you get 0 1 2.
在第一个样例测试中,当你第一次按下按钮时,活动齿的序列为 2 2 1;当你第二次按下按钮时,得到 0 1 2。
输入解题思路,AI测评打分。不知道怎么写?