CF451C.Predict Outcome of the Game
普及+/提高
通过率:0%
时间限制:2.00s
内存限制:256MB
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题目描述
There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played.
You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of wins of each team, instead he thought that absolute difference between number of wins of first and second team will be _d_1 and that of between second and third team will be _d_2.
You don't want any of team win the tournament, that is each team should have the same number of wins after n games. That's why you want to know: does there exist a valid tournament satisfying the friend's guess such that no team will win this tournament?
Note that outcome of a match can not be a draw, it has to be either win or loss.
一场足球锦标赛共有 n 场比赛,有三支队伍参加。目前已有 k 场比赛结束。
你是一位狂热的足球迷,但最近你错过了全部这 k 场比赛。幸运的是,你还记得朋友对这 k 场比赛结果所作的一个猜测:朋友并未告诉你每支队伍确切的胜场数,而是猜测:第一支队伍与第二支队伍的胜场数之差的绝对值为 d1,第二支队伍与第三支队伍的胜场数之差的绝对值为 d2。
你不希望任何一支队伍最终赢得整个锦标赛,即:在全部 n 场比赛结束后,三支队伍的胜场数必须完全相等。因此你想知道:是否存在一种符合朋友猜测的、合法的比赛结果安排,使得最终没有任何一支队伍获胜?
注意:每场比赛的结果不能为平局,只能是一方获胜、另一方失利。
输入格式
The first line of the input contains a single integer corresponding to number of test cases t (1 ≤ t ≤ 105).
Each of the next t lines will contain four space-separated integers n, k, _d_1, _d_2 (1 ≤ n ≤ 1012; 0 ≤ k ≤ n; 0 ≤ _d_1, _d_2 ≤ k) — data for the current test case.
输入的第一行包含一个整数,表示测试用例的数量 t(1 ≤ t ≤ 105)。
接下来的 t 行中,每行包含四个以空格分隔的整数 n、k、d1、d2(1 ≤ n ≤ 1012;0 ≤ k ≤ n;0 ≤ d1, d2 ≤ k),表示当前测试用例的数据。
输出格式
For each test case, output a single line containing either "yes" if it is possible to have no winner of tournament, or "no" otherwise (without quotes).
对于每个测试用例,输出一行,如果有可能使锦标赛没有获胜者,则输出“yes”(不带引号),否则输出“no”(不带引号)。
输入输出样例
输入#1
5 3 0 0 0 3 3 0 0 6 4 1 0 6 3 3 0 3 3 3 2
输出#1
yes yes yes no no
说明/提示
Sample 1. There has not been any match up to now (k = 0, _d_1 = 0, _d_2 = 0). If there will be three matches (1-2, 2-3, 3-1) and each team wins once, then at the end each team will have 1 win.
Sample 2. You missed all the games (k = 3). As _d_1 = 0 and _d_2 = 0, and there is a way to play three games with no winner of tournament (described in the previous sample), the answer is "yes".
Sample 3. You missed 4 matches, and _d_1 = 1, _d_2 = 0. These four matches can be: 1-2 (win 2), 1-3 (win 3), 1-2 (win 1), 1-3 (win 1). Currently the first team has 2 wins, the second team has 1 win, the third team has 1 win. Two remaining matches can be: 1-2 (win 2), 1-3 (win 3). In the end all the teams have equal number of wins (2 wins).
样例 1:截至目前尚未进行任何比赛(k=0,d1=0,d2=0)。若接下来进行三场比赛(1–2、2–3、3–1),且每支队伍各赢一场,则最终每支队伍均恰好有 1 场胜利。
样例 2:你错过了全部三场比赛(k=3)。由于 d1=0 且 d2=0,而存在一种进行三场比赛且不产生锦标赛冠军的方式(如前一样例所述),因此答案为“是”。
样例 3:你错过了 4 场比赛,且 d1=1,d2=0。这四场比赛可以是:1–2(2 获胜)、1–3(3 获胜)、1–2(1 获胜)、1–3(1 获胜)。此时第一支队伍有 2 场胜利,第二支队伍有 1 场胜利,第三支队伍有 1 场胜利。剩余两场比赛可以是:1–2(2 获胜)、1–3(3 获胜)。最终,所有队伍的获胜场数相等(均为 2 场胜利)。
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