CF216E.Martian Luck
普及+/提高
通过率:0%
时间限制:2.00s
内存限制:256MB
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题目描述
You know that the Martians use a number system with base k. Digit b (0 ≤ b < k) is considered lucky, as the first contact between the Martians and the Earthlings occurred in year b (by Martian chronology).
A digital root d(x) of number x is a number that consists of a single digit, resulting after cascading summing of all digits of number x. Word "cascading" means that if the first summing gives us a number that consists of several digits, then we sum up all digits again, and again, until we get a one digit number.
For example, d(35047) = d((3 + 5 + 0 + 4)7) = d(157) = d((1 + 5)7) = d(67) = 67. In this sample the calculations are performed in the 7-base notation.
If a number's digital root equals b, the Martians also call this number lucky.
You have string s, which consists of n digits in the k-base notation system. Your task is to find, how many distinct substrings of the given string are lucky numbers. Leading zeroes are permitted in the numbers.
Note that substring s[i... j] of the string s = _a_1_a_2... a__n (1 ≤ i ≤ j ≤ n) is the string a__i__a__i + 1... a__j. Two substrings s[_i_1... _j_1] and s[_i_2... _j_2] of the string s are different if either _i_1 ≠ _i_2 or _j_1 ≠ _j_2.
你知道火星人使用以 k 为底的进制数系统。数字 b(其中 0≤b<k)被视为幸运数字,因为火星人与地球人的首次接触发生在火星历的第 b 年。
一个数 x 的数字根 d(x) 是指将 x 的所有数位反复相加,直至结果为一位数后所得的数。“反复”意味着:若第一次求和得到的数仍含多位数字,则需继续对其各位数字求和,如此反复,直到结果为一位数为止。
例如,d(35047)=d((3+5+0+4)7)=d(157)=d((1+5)7)=d(67)=67。本例中所有计算均在七进制下进行。
若一个数的数字根等于 b,火星人也将该数称为幸运数。
现给你一个字符串 s,它由 n 个 k 进制数字组成。你的任务是:找出该字符串中有多少个互不相同的子串是幸运数。允许子串带前导零。
注意:字符串 s=a1a2…an(其中 1≤i≤j≤n)的子串 s[i…j] 定义为字符串 aiai+1…aj。字符串 s 的两个子串 s[i1…j1] 和 s[i2…j2] 被视为不同,当且仅当 i1=i2 或 j1=j2。
输入格式
The first line contains three integers k, b and n (2 ≤ k ≤ 109, 0 ≤ b < k, 1 ≤ n ≤ 105).
The second line contains string s as a sequence of n integers, representing digits in the k-base notation: the i-th integer equals a__i (0 ≤ a__i < k) — the i-th digit of string s. The numbers in the lines are space-separated.
第一行包含三个整数 k、b 和 n(2 ≤ k ≤ 109,0 ≤ b < k,1 ≤ n ≤ 105)。
第二行包含字符串 s,以 n 个整数的序列形式给出,表示 k 进制下的各位数字:第 i 个整数等于 ai(0 ≤ ai < k),即字符串 s 的第 i 位数字。行中的数字以空格分隔。
输出格式
Print a single integer — the number of substrings that are lucky numbers.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
输出一个整数——幸运数字子串的个数。
请注意,在 C++ 中读写 64 位整数时,请勿使用 %lld 说明符。推荐使用 cin、cout 流,或 %I64d 说明符。
输入输出样例
输入#1
10 5 6 3 2 0 5 6 1
输出#1
5
输入#2
7 6 4 3 5 0 4
输出#2
1
输入#3
257 0 3 0 0 256
输出#3
3
说明/提示
In the first sample the following substrings have the sought digital root: s[1... 2] = "3 2", s[1... 3] = "3 2 0", s[3... 4] = "0 5", s[4... 4] = "5" and s[2... 6] = "2 0 5 6 1".
在第一个样例中,以下子串具有所求的数字根:s[1...2] = "3 2",s[1...3] = "3 2 0",s[3...4] = "0 5",s[4...4] = "5",以及 s[2...6] = "2 0 5 6 1"。
输入解题思路,AI测评打分。不知道怎么写?