CF49A.Sleuth

Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to answer the questions like that: if the question’s last letter is a vowel, they answer "Yes" and if the last letter is a consonant, they answer "No". Of course, the sleuth knows nothing about it and his task is to understand that.

Unfortunately, Vasya is not very smart. After 5 hours of endless stupid questions everybody except Vasya got bored. That’s why Vasya’s friends ask you to write a program that would give answers instead of them.

The English alphabet vowels are: A, E, I, O, U, Y

The English alphabet consonants are: B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, X, Z

瓦西娅和朋友们一起玩侦探游戏。游戏规则如下：首次参与游戏的人（即瓦西娅）担任侦探，需调查一起“案件”并弄清事情真相。他可以提出任意问题，但所有问题都只能以“是”或“否”来回答。其余所有人预先约定按如下方式回答问题：若问题的最后一个字母是元音字母，则回答“是”；若最后一个字母是辅音字母，则回答“否”。当然，侦探对此一无所知，他的任务就是发现这一规律。

不幸的是，瓦西娅并不太聪明。在连续 5 小时毫无意义的提问之后，除瓦西娅外的所有人都感到厌烦。因此，瓦西娅的朋友们请你编写一个程序，代替他们来回答问题。

英语字母中的元音字母为：A、E、I、O、U、Y
英语字母中的辅音字母为：B、C、D、F、G、H、J、K、L、M、N、P、Q、R、S、T、V、W、X、Z

The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter.

单行输入包含一个由非空字符串表示的问题，该字符串由大写和小写的拉丁字母、空格以及一个问号组成。字符串长度不超过 100。保证问号恰好在该行中出现一次，且位于最后一个字符位置，并且该行至少包含一个字母。

Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".

Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters.

单行输出问题的答案：如果答案是“是”，则输出 YES；如果答案是“否”，则输出 NO。

注意：在回答该问题时，以最后一个字母（而非最后一个字符）为准。即空格和问号等非字母字符不视为字母。