#include<cstdio> int a,b,c,n; int main(){ scanf("%d%d%d%d",&n,&a,&b,&c); printf("%d",(n-c+b-a-1)/(b-a)); return 0; } 666斜体文本

#include <cstdio> int main() { long long n, a, b, c; scanf("%lld%lld%lld%lld", &n, &a, &b, &c); printf("%lld", (n - c + b - a - 1) / (b - a)); return 0; } 或者更清晰版： #include <cstdio> int main() { long long n, a, b, c; scanf("%lld%lld%lld%lld", &n, &a, &b, &c); long long need = n - c; long long speed_diff = b - a; long long ans = (need + speed_diff - 1) / speed_diff; printf("%lld\n", ans); return 0; }