#include <bits/stdc++.h> using namespace std; void baron(int a,int b){ int x=2; long long day=pow(a,b); cout<<day%7; } int main(){ int a,b; cin>>a>>b; baron(a,b); }

AC

不会的都看我！ 100%AC！ 点个关注！

代码复杂度: O(n) 这题目很"简单" 90tps: 错了？？？ ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ 原来没有考虑ans被7整除时输出为0的情况！ 100tps: // A7852 AC

代码如下：

https://www.gnomic.cn/agentChat/index?ax（CHATGPT4.0）

a,b=map(int, input().split()) days=a**b if days%7==0: weekday=7 else: weekday=days%7 print(weekday)

#include <bits/stdc++.h> using namespace std; void dog(int a,int b){ long long x=pow(a,b); int y=x%7; if(y==0) cout<<7; else cout<<y; } int main(){ int n; int m; cin>>n>>m; dog(n,m); return 0; }

#include<bits/stdc++.h> using namespace std; int main() { long long a,b; cin>>a>>b; cout<< pow(a,b)%7 ; return 0 ; }

#include<bits/stdc++.h> using namespace std; int a,b; long long sum; int main(){ cin >> a >> b; sum = pow(a,b); if(sum <= 7){ cout << sum; }else{ if(sum % 7 == 0){ cout << "7"; }else{ cout << sum % 7; } } return 0; }