#include<iostream> using namespace std; int main(){ long long a,b,c; cin>>a>>b>>c; cout<<a+b+c; return 0; }

注意是10的9次方。 如果有帮助就点个赞吧

还有人只用两变量吗？

#include<bits/stdc++.h> using namespace std; int main() { long long a,b,c; cin>>a>>b>>c; cout<<a+b+c; return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ long long a,b,c; cin>>a>>b>>c; cout<<a+b+c; }

#include<bits/stdc++.h> using namespace std; int main(){ unsigned long long a,b,c; cin>>a>>b>>c; cout<<a+b+c; }

#include<bits/stdc++.h> using namespace std; int main(){ long long a,b; cin>>a>>b; a+=b; cin>>b; a+=b; cout<<a; }

#include<iostream> using namespace std; int main(){ long long a[4],s; for(int i=1;i<=3;i++) { cin>>a[i]; s+=a[i]; } cout<<s; return 0; }

#include<iostream> using namespace std;int main(){long long a,b,c;cin>>a>>b>>c;cout<<a+b+c; return 0;}

A+B+C Problem

差一点翻船 加油！特种兵！

#include <cstdio> long long a, b, c; int main(){scanf("%ld %ld %ld", &a, &b, &c);printf("%ld", a + b + c);}