#include <bits/stdc++.h> using namespace std; int main(){ int a=2200,b=4396; cout <<b<<'+'<<a<<'='<<a+b<<endl; cout <<b<<'-'<<a<<'='<<b-a<<endl; cout <<b<<''<<a<<'='<<ba<<endl; cout <<b<<'/'<<a<<'='<<b/a<<endl; cout <<b<<'%'<<a<<'='<<b%a; return 0; }

众所周知，这种简简单单的计算题是一年级的小朋友们都可以口算的。 所以，废话不多说，上最少内存的题解！ 等等 点击加入“ACGO的AC团”

#include<bits/stdc++.h> using namespace std; int n=4396,m=2200; int main(){ cout<<n<<"+"<<m<<"="<<n+m<<"\n"; cout<<n<<"-"<<m<<"="<<n-m<<"\n"; cout<<n<<""<<m<<"="<<nm<<"\n"; cout<<n<<"/"<<m<<"="<<n/m<<"\n"; cout<<n<<"%"<<m<<"="<<n%m<<"\n"; return 0; }

#include<iostream> int main(){std::cout<<"4396+2200=6596\n4396-2200=2196\n4396*2200=9671200\n4396/2200=1\n4396%2200=2196";}

#include <bits/stdc++.h> using namespace std; int main(){ cout<<"4396+2200="<< 4396+2200<<endl; cout<<"4396-2200="<< 4396-2200<<endl; cout<<"43962200="<< 43962200<<endl; cout<<"4396/2200="<< 4396/2200<<endl; cout<<"4396%2200="<<4396%2200; return 0; }

#include <bits/stdc++.h> using namespace std; int main(){ cout<<4396<<"+"<<2200<<"="<<4396+2200<<endl; cout<<4396<<"-"<<2200<<"="<<4396-2200<<endl; cout<<4396<<""<<2200<<"="<<43962200<<endl; cout<<4396<<"/"<<2200<<"="<<4396/2200<<endl; cout<<4396<<"%"<<2200<<"="<<4396%2200<<endl; return 0; }

#include <bits/stdc++.h> using namespace std; int main() { long long a=4396,b=2200; cout<<"4396"<<"+"<<"2200"<<"="<<a+b<<endl; cout<<"4396"<<"-"<<"2200"<<"="<<a-b<<endl; cout<<"4396"<<""<<"2200"<<"="<<ab<<endl; cout<<"4396"<<"/"<<"2200"<<"="<<a/b<<endl; cout<<"4396"<<"%"<<"2200"<<"="<<a%b<<endl; return 0; }