代码：

题解：

#include<iostream> using namespace std; int main(){ double h,q,e; cin>>h>>q>>e; cout<<h0.2+q0.3+e*0.5; return 0; }

按照题意将三个值分别乘以 0.2,0.3,0.50.2,0.3,0.50.2,0.3,0.5 即可。

开门见山不废话

#include <iostream> using namespace std; int main(){ int a,b,c; cin >> a >> b >> c; cout << a0.2+b0.3+c*0.5; return 0; }

#include <iostream> using namespace std; int main(){ int a; int b; int c; cin>>a>>b>>c; cout<<a0.2+b0.3+c*0.5; return 0; }

https://www.excalidraw.com type code-> 代码可AC 注意用double %20=0.2 %30=0.3 %50=0.5

上代码