print(5)

#include<bits/stdc++.h> using namespace std; int a,b; int ab(){ int n=92345678984; if(a>=-87654378765127876543456787654){ n+=a; }else{ n+=653987654678; } for(int i=1;i<=1;i++){ n+=b; } n-=92345678984; return n; } int main(){ long long c=567876445+56788456-4567654+456780+1,d=-34532+1e20+100-99; while(c+c2){ c++; } c=d100000+1000-999; if(1+1!=2){ cout << "ababababababababababababababababab"; }else if(c+c!=2){ cout << "What f***!"; }else{ //cout << "!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!"; bool asugud_757sd8s=true; } for(int i=1;i<=1;i++){ long long x=11089976; string s; char ch=' '; if(c+99!=100){ cout << x; cout << s; cout << ch; } } if(1*22){ cin >> a >> b; }else{ cout << "???????????????????????????????????????????????????????????????????????"; } if(00==0){ cout << ab(); }else if(71000==686443){ cout << 6; }else{ cout << "我癌++c!"; } return 0; } //:P

#include<iostream> #include<cmath> using namespace std; int a_b_problem(int a,int b){ return a+b; } int main(){ int a,b; cin>>a>>b; cout<<a_b_problem(a,b); return 0; }

#include<iostream> #include<cmath> using namespace std; int a_b_problem(int a,int b){ return a+b; } int main(){ int a,b; cin>>a>>b; cout<<a_b_problem(a,b); return 0; }

#include <bits/stdc++.h> int main(){long long **,TMD;stdcin >> ** >> TMD;stdcout << **+TMD;return 0;}

#include<iostream> using namespace std; int main() { int a, b; cin >> a >> b; cout << a + b; return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ int m,n; cin>>m>>n; cout<<m+n; }

#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; } //irjfijdoijgnfjngfufhesjfijfffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff

#include<bits/stdc++.h> int main(){ std::cout<<5; }

#include <bits/stdc++.h> using namespace std; int a[1000000]; int k; struct node{ int val,id; friend bool operator <(const node &a,const node&b){ if(a.val != b.val){ return a.val<b.val; } else{ return a.id>b.id; } } }; int main(){ freopen("monster.in","r",stdin); freopen("monster.out","w",stdout); int n,k; cin >>n>>k; priority_queue<node>g; for(int i = 1;i<=n;i++){ int val; cin >>val; g.push({val,i}); } while(!g.empty()){ node fr = g.top(); g.pop(); fr.val -= k; if(fr.val <=0){ cout <<fr.id<<" "; continue; } g.push(fr); } fclose(stdin); fclose(stdout); return 0; }

题目分析 题目要求我们输入两个数字后输出两数之和。 观察数据范围:（0<=a,b<=1090<=a,b<=10^90<=a,b<=109） 而INT_MAX的值为2147483647 也就是说这并不会爆int。 因此代码如下:

//正经题解看这里 :) #include <bits/stdc++.h> using namespace std; int a,b; int main() { cin>>a>>b; cout<<a+b; return 0; }

题目分析 输入两个整数，输出它们的和。 我们可以用 scanf() 函数来实现输入，再用 printf() 函数来实现输出。 代码实现 > 记得五星好评哦喵~ 谢谢客官啦~

#include<iostream> using namespace std; int main(){ long long a,b; cin>>a>>b; cout<<a+b; return 0; }

#include <iostream> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; return 0; }