很简单直接运算即可，由于数据很小开int即可AC INCLUDE <BITS/STDC++.H> using namespace std; int x,y,z,t; double ans; int main() { scanf("%d%d%d%d",&t,&x,&y,&z); ans=xy/(double)8z*t; ans=ans/(double)1024/(double)1024; printf("%0.4lf",ans); }