#include <iostream> using namespace std; int main(){ int n; cin>>n; if(n>=10&&n<=99) { cout<<1; } else { cout<<0; } return 0; }

题解如下，十分简单： #include<iostream> using namespace std; int main(){ int n; cin>>n; if(n>=10&&n<=99){ cout<<1; }else{ cout<<0; } }

最短

#include<iostream> using namespace std; int main(){ int a;//定义 cin>>a;//输入 if(a>=10 and a<=99){//判断 cout<<1; }else{ cout<<0; } return 0; }

a=int(input()) b=0 if a>=10 and a<=99: print(1) else: print(0)

代码：

**a = int(input()) if a >= 10 and a <= 99: print('1') else: print('0')**法

水题

🫥🫠 #include<iostream> #include<string> using namespace std; string s; int main(){ cin>>s; printf("%d",(s.length()==2)); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ int a; cin>>a; if(a>=10&&a<=99){ cout<<1; } else{ cout<<0; } return 0; }

a = input() b = 0 for i in a: b += 1 if b == 2: print(1) else: print(0)