cost=5.522+6.645+25*10 remain=1000-cost print(f'他一共花了{int(cost)}块钱，还剩{int(remain)}块钱。')

#include<iostream> using namespace std; int main(){ double n=5.522+6.645+25*10; cout<<"他一共花了"<<n<<"块钱，还剩"<<1000-n<<"块钱。"; return 0; }