利用i j 去模拟题目

#include<bits/stdc++.h> using namespace std; int main(){ int n,num=1; string s1,s2; cin >> s1 >>n; while(n){ s2=""; for(int i=0;i<s1.size();i++){ if(i<s1.size()-1&&s1[i]==s1[i+1]) num++; else{ s2+=to_string(num)+s1[i]; num=1; } } s1=s2; n--; } cout<<s2; }

我过关！ 代码：

#include <unistd.h> static char inBuf[1 << 10]; static int inLen = 0, inPos = 0; inline int readChar() { if (inPos == inLen) { inLen = read(0, inBuf, sizeof(inBuf)); inPos = 0; if (inLen <= 0) return -1; } return inBuf[inPos++]; } static char s[2][1000005]; int main() { // 读入初始串 int len = 0; int c = readChar(); while (c <= ' ') { if (c == -1) return 0; c = readChar(); } while (c > ' ') { s[0][len++] = (char)c; c = readChar(); } }

题解： #include <iostream> #include <cstdio> #include <cstring> using namespace std; int main(){ string a; cin >> a; int aaa; cin >> aaa; while(aaa--){ string b;//临时字符串 for(int i = 0; i < a.length();){ int j = i; while(j < a.length()){ if(a[j] != a[i]) break; j++; }//计算有几个连续的相同的数 b += (to_string(j - i) + a[i]);//加入临时字符串 i = j; }a = b;//更新字符串 }cout << a; }