#include <iostream> using namespace std; void f(){ int n,m,a[105],sum=0;//个人习惯多5个,可修改 cin>>n>>m; for(int i=0;i<n;++i) cin>>a[i]; for(int i=0;i<n;++i){ if(m<a[i]){ sum+=a[i]-m; m=0; } else m-=a[i]; } cout<<sum<<endl; } int main(){ int t; cin>>t; for(int i=0;i<t;++i) f(); return 0; }

by QFIT 点此加盟

#include <iostream> using namespace std; int main() { int t; cin>>t; while (t--) { int n,m; cin>>n>>m; int a=0,x=0; for (int i=1;i<=n;i++) { cin>>x; a+=x; } if (m-a>0) cout<<0<<endl; else cout<<a-m<<endl; } return 0; }