只需要按题目要求顺序遍历数组，还原序列

#include<iostream> using namespace std; int main() { int a[10001],n,t,zh,i=0; cin>>t; for(int y=1;y<=t;y++) { zh=1; a[10001]={}; cin>>n; i=n; for(int y=1;y<=n;y++) { cin>>a[y]; } if(n%2==0) { for(int y=1;y<=n/2;y++) { cout<<a[zh]<<" "; cout<<a[i]<<" "; zh=zh+1; i=i-1; } }

#include<bits/stdc++.h> #include<iostream> #include<cmath> using namespace std; const int N=310; int n; int a[N]; int b[N]; void z(int s){ if(s%2==1){ int s1=(s+1)/2; for(int i=0,j=0;i<s1;i++,j+=2){ b[j]=a[i]; } int main(){ }