这样做的： #include <iostream> using namespace std; int main() { int x, y; if (cin >> x >> y && 1 <= x && x <= 1000 && 1 <= y && y <= 1000) { int a = 4 * x - y; int b = a / 2; if (a % 2 == 0 && b >= 0 && b <= x) { cout << b << endl << x - b << endl; } else { cout << "No solution" << endl; } } else { cout << "Invalid input" << endl; } return 0; }

1+1=1就可以做了

在做奥数时很难，但在C++中好简单！

#include<iostream> using namespace std; int main(){ int x,y; cin>>x>>y; int a,b; int num=y-2*x; b=num/(4-2); a=x-b; cout<<a<<endl<<b; return 0; }