翻日历法

大家不要学习，就图一乐

#include<bits/stdc++.h>
using namespace std;
int a[6][8];
int main(){
    cout<<"MON TUE WED THU FRI SAT SUN\n";
    int n;
    cin>>n;
    int j;
    int m;
    //翻日历法
    switch(n){
        case 1:j=3,m=31;break;
        case 2:j=6,m=28;break;
        case 3:j=6,m=31;break;
        case 4:j=2,m=30;break;
        case 5:j=4,m=31;break;
        case 6:j=7,m=30;break;
        case 7:j=2,m=31;break;
        case 8:j=5,m=31;break;
        case 9:j=1,m=30;break;
        case 10:j=3,m=31;break;
        case 11:j=6,m=30;break;
        case 12:j=1,m=31;break;
    }
    int c=0;
    for(int i=1;i<=m/7+2;i++){
        for(int k=1;k<=7;k++){
            if(i==1 && k <= j-1){
                cout<<"    ";
                continue;
            }
            //直接用printf就行图一乐
            if(c==m) break;
            if(++c<10) cout<<" ";
            cout<<" "<<c<<" ";
        }
        cout<<endl;
    }
    return 0;
}