A7851.完成回文数判定函数 题解

#include <iostream>
using namespace std;
bool is_pal(int n){
	int x = 0, y = n; //x用于储存n的颠倒过来的数
	while (y!=0){
		 x = x*10+y%10 ;
		 y = y/10;
	}
	if (x==n){
		return true;
	}else{
		return false;
	}
}
int main(){
	int n;
	cin >> n;
	if (is_pal(n))
		cout << "Yes" << endl;
	else
		cout << "No" << endl;
	return 0;
}