
```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
	int l,r;
	int x,ans;
	while(l<=r){
		int mid=(l+r)/2;
		if(mid==x){
			ans==x;
		}else if(mid>x){
			r=mid-1;
		}else{
			l=mid+1;
		}
	}
	cout<<ans;
	return 0;
} 
```


倔强青铜


```cpp
#include<bits/stdc++.h> 
using namespace std;
int main(){
	int l=0,r=2048;//二分范围 
	int ans=0;
	while(l<=r){
		int mid=(l+r)/2;
		if(mid==ans){
			break;
		}else if(mid>ans){
			r=mid-1;
		}else{
			l=mid+1;
		}
	}
cout<<ans; 
	return 0;
}
```


二分查找

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