数学法 | O(N)

由题目可知m的值其实等于p+q
接下来，通过获取mm-4n并分解可知sqrt(mm-4n) = q-p

#include<iostream>
#include<cmath>
using namespace std;
int main(){
    int t;
    cin >> t;
    while(t--){
        long long n, e, d, p, q, m, ans,sq;
        cin >> n >> e >> d;
        m = n-(e*d)+2;
        ans = m*m - 4*n;
        sq = sqrt(ans);
        if(sq*sq!=ans)cout << "NO";
        else{
            p = (m-sq)/2;
            q = (m+sq)/2;
            cout << min(p, q) << " " << max(p, q);
        }
        cout << endl;
    }
}