内存要求最少的程序（2.35MB）

#include <math.h>

int main() {
    int n, x, y;
    scanf("%d %d %d", &n, &x, &y);
    int z[n][2];
    double mx = -1;
    
    for (int i = 0; i < n; i++) {
        scanf("%d %d", &z[i][0], &z[i][1]);
    }
    
    for (int i = 0; i < n; i++) {
        int tx = x;
        int ty = y;
        tx += z[i][0];
        ty += z[i][1];
        
        if (tx > 100) {
            int r = tx - 100;
            tx = 100;
            ty += r * 3;
        }
        
        double q = 10000 * (tx / 100.0) * (1 + ty / 100.0) + 10000 * ((100 - tx) / 100.0) * 1;
        if (q > mx) {
            mx = q;
        }
    }
    
    printf("%d\n", (int)ceil(mx));
    return 0;
}