A669.子串判定 题解

#include<bits/stdc++.h>
using namespace std;

int main(){
    string a,b,c,s;
    cin>>a>>b>>c;
    s+=a;s+=b;//拼接
    if(s.find(c)!=string::npos/*string::npos 没找到*/) cout<<c<<" is substring of "<<a<<" and "<<b;//find函数：寻找子串
    else cout<<c<<" is not substring of "<<a<<" and "<<b;
    return 0;
}

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