A524.排队照相 题解

#include<bits/stdc++.h>
using namespace std;

int main(){
    int n;
    int b[105],g[105],bl = 0,gl = 0,num;
    cin>>n;
    for(int i = 0;i<n;i++){
        cin>>num;
        if(num>0) b[bl] = num,bl++;
        else g[gl] = num,gl++;
    }
    sort(b,b+bl);
    sort(g,g+gl);//懒得写快排，用sort
    //----------输出----------
    for(int i = 0;i<bl;i++){
        cout<<b[i]<<" ";
    }
    for(int i = 0;i<gl;i++){
        cout<<g[i]<<" ";
    }
    return 0;
}