题解 | A467.判断n位数
2025-10-25 15:59:35
发布于:广东
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#include <bits/stdc++.h>
using namespace std;
int main() {
int x , n;
cin >> x >> n;
if(n == 1){
if(x >= 0 && x <= 9){
cout << "Yes";
}
else{
cout << "No";
}
}
if(n == 2){
if(x >= 10 && x <= 99){
cout << "Yes";
}
else{
cout << "No";
}
}
if(n == 3){
if(x >= 100 && x <= 999){
cout << "Yes";
}
else{
cout << "No";
}
}
if(n == 4){
if(x >= 1000 && x <= 9999){
cout << "Yes";
}
else{
cout << "No";
}
}
return 0;
}
这里空空如也


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