题解

如下↓

#include <bits/stdc++.h>
#include <iostream>
using namespace std;
int main(){
    int n,a[1240],count_odd=0,count_even=0;
    cin>>n;
    for (int i=0;i<=n;i++){
        cin>>a[i];
    }
    for (int j=0;j<n;j++){
        if(a[j]%2==0){
            count_even+=1;
        }else{
            count_odd+=1;
        }
    }cout<<count_odd<<" "<<count_even;
}