NOIP2024T4:
知周所众:
LCA∗(l,r)=l≤i≤r−1mindeplca(i,i+1)
求
l≤l′≤r′≤r,r′−l′+1≥kmaxdepLCA∗(l′,r′)
知周所众:
l≤l′≤r′≤r,r′−l′+1≥kmaxdepLCA∗(l′,r′)≤l≤l′≤r′≤r,r′−l′+1=kmaxdepLCA∗(l′,r′)
⟹l≤l′≤r′≤r,r′−l′+1=kmaxdepLCA∗(l′,r′)
⟹l≤l′≤r′≤r,r′−l′+1=kmax(l′≤i≤r′−1mindeplca(i,i+1))
⟹l≤l′≤l′+k−1≤rmax(l′≤i≤l′+k−2mindeplca(i,i+1))
综上得到答案表达式:
ans=l≤l′≤l′+k−1≤rmax(l′≤i≤l′+k−2mindeplca(i,i+1))
本人是蒟蒻,推导若有错误请指正

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