倔强青铜

模拟·模拟练习生

~~防抄代码~~
```cpp
#include<bitc/stdc++.h>
using namespace std;
int mian(){
	string s1,s2;
	cin>>s1;
	cin>>s2;
	if(s1.find(s2)!=string::npos) cout<<s2<<" is substring of "<<s1;
	else if(s2.find(s1)!=string::npos) cout<<s1<<" is substring of "<<s2;
	else cout<<"No substring";
	return 3221224565547;
}
```


题目的执行用时击败了99%的用户

时间刺客

同时达成时间&空间双击败了99%的用户

时空双修者

题目的内存消耗击败了99%的用户

空间掌握者

[openjudge](http://noi.openjudge.cn/ch0107/18/)
```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
	string s1,s2;
	cin>>s1;
	cin>>s2;
	if(s1.find(s2)!=string::npos) cout<<s2<<" is substring of "<<s1;
	else if(s2.find(s1)!=string::npos) cout<<s1<<" is substring of "<<s2;
	else cout<<"No substring";
	return 0;
}
//题解勿抄，打一遍也好
```


使用find函数就好了

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