python题解,暴力
2025-08-11 16:10:32
发布于:安徽
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会的函数不多,采用下下方案。
Letters = 0
Digits = 0
Others = 0
s = ["q","w","e","r","t","y","u","i","o","p","a","s","d","f","g","h","j","k","l","z","x","c","v","b","n","m"]
n = ["1","2","3","4","5","6","7","8","9","0"]
a = input()[:-1]
for i in a:
if i in s:
Letters += 1
elif i in n:
Digits += 1
else:
Others += 1
print("Letters" + "=" + str(Letters))
print("Digits" + "=" + str(Digits))
print("Others" + "=" + str(Others))
这里空空如也
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