题解

要点：min(min(a,b),c)
参考代码：

#include <bits/stdc++.h>
using namespace std;

int main(){
    long long t,a,b,c;
    cin >> t;
    for (int i = 1;i <= t;i++){
        cin >> a >> b >> c;
        cout << min(min(a / 2,b / 4),c / 1) << endl; 
    }
    return 0;
}