只学过三目运算符和循环的孩子们也能通过了

#include<bits/stdc++.h>
using namespace std;
char hs[20]={1,0,1,0,0,0,0,2,0,11,13,0,0,0,0,0,12,0,3,10};
//hs['abc'-'A']=1,2,3,4,10,11,12,13
bool poker[60];
int main(){
    int n;
    cin >> n;
    for ( int i=0; i<n; i++){
        string s;
        cin >> s;
        poker[hs[s[0]-'A']*13+(s[1]<='9'?s[1]-'0':hs[s[1]-'A'])-1]=true;
    }
    char sum=0;
    for ( int i=0; i<52; i++){
        sum += poker[i];
    }
    cout << 52-(int)sum;
}