只学过分支 循环的孩子们也能做这个题了

核心思路：写一个密码，把字符转化为数字

#include <bits/stdc++.h>
using namespace std;
int n,a[60],sum;
int main(){
    cin>>n;
    while(n--){
        string s;
        int w=0;
        cin>>s;
        for(int i=0;i<2;i++){
            if(s[i]=='A') w+=1;
            else if(s[i]=='2') w+=2;
            else if(s[i]=='3') w+=3;
            else if(s[i]=='4') w+=4;
            else if(s[i]=='5') w+=5;
            else if(s[i]=='6') w+=6;
            else if(s[i]=='7') w+=7;
            else if(s[i]=='8') w+=8;
            else if(s[i]=='9') w+=9;
            else if(s[i]=='T') w+=10;
            else if(s[i]=='J') w+=11;
            else if(s[i]=='Q') w+=12;
            else if(s[i]=='S'||s[i]=='K') w+=13;
            else if(s[i]=='D') w+=26;
            else if(s[i]=='C') w+=39;
        }
        if(a[w]==0){
            sum++;
            a[w]=1;
        }
    }
    cout<<52-sum;
    return 0;
}