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无敌的鳖佬仔给老爷爷猜猜被

2024-10-26 12:31:20

发布于：浙江

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def convert_to_base(X, M): 
    # 递归终止条件 
    if X == 0: 
        return "" 
     
    # 计算余数 
    remainder = X % M 
     
    # 将余数转换为对应的字符 
    if remainder < 10: 
        remainder_char = str(remainder) 
    else: 
        remainder_char = chr(ord('A') + remainder - 10) 
     
    # 递归调用 
    return convert_to_base(X // M, M) + remainder_char 
 
# 输入处理 
X, M = map(int, input().split()) 
 
# 特殊处理：如果X为0，直接输出0 
if X == 0: 
    print(0) 
else: 
    print(convert_to_base(X, M))

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鱼儿

#include <iostream>
#include <string>
using namespace std;

string convert_to_base(int a, int b) {
    if (a == 0) {
        return "";
    }
    int c = a % b;
    char c_char;
    if (c < 10) {
        c_char = '0' + c;
    } else {
        c_char = 'A' + c - 10;
    }
    return convert_to_base(a / b, b) + c_char;
}

int main() {
    int a, b;
    cin >> a >> b;
    if (a == 0) {
        cout << 0 << endl;
    } else {
        cout << convert_to_base(a, b) << endl;
    }
    return 0;
}

昨天来自浙江

鱼儿
#include <iostream>
#include <string>
using namespace std;

string convert_to_base(int a, int b) {
if (a == 0) {
return "";
}
int c = a % b;
char c_char;
if (c < 10) {
c_char = '0' + c;
} else {
c_char = 'A' + c - 10;
}
return convert_to_base(a / b, b) + c_char;
}

int main() {
int a, b;
cin >> a >> b;
if (a == 0) {
cout << 0 << endl;
} else {
cout << convert_to_base(a, b) << endl;
}
return 0;
}

昨天来自浙江
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