极简题解

太简单力！有手就行

#include<bits/stdc++.h>
using namespace std;

int n,a[5005],k,ans;

int main()
{
	cin >> n;
	for(int i = 1;i <= n;i++)
	{
		cin >> a[i];
	}
	cin >> k;
	for(int i = 1;i <= n;i++)
	{
		if(a[i] == k)
			ans++;
	}
	cout << ans;
	return 0;
}