结果

#include<bits/stdc++.h>
using namespace std;
struct preson{
string name;
}a[110];
int main() {
int n,ca=0,cb=0,cc=0;cin>>n;
for(int i=1;i<=n;i++){
cin>>a[i].name;
if(a[i].name=="Li"){
ca+=1;
}else if(a[i].name=="Zhang"){
cb+=1;
}else if(a[i].name=="Fun"){
cc+=1;
}
}
cout<<"Li:"<<ca<<endl<<"Zhang:"<<cb<<endl<<"Fun:"<<cc;
return 0;
}