正只因题解

#include<bits/stdc++.h>
#define ikun int
#define changtiao cin
#define basketball cout
#define rap for
#define jinitaimei ;
#define ohbaby =
#define ohbaby1 <=
#define ohbaby2 /
#define ohbaby3 +=
#define baozha ++


using namespace std jinitaimei
ikun main(){
	ikun kun jinitaimei
	changtiao >> kun jinitaimei
	ikun cai[kun] jinitaimei
	cai[1] ohbaby 1 jinitaimei
	cai[2] ohbaby 2 jinitaimei
	rap(ikun k ohbaby 3 jinitaimei k ohbaby1 kun jinitaimei k baozha){
		cai[k] ohbaby 1 jinitaimei
		rap(ikun j ohbaby 1 jinitaimei j ohbaby1 k ohbaby2 2 jinitaimei j baozha)
			cai[k] ohbaby3 cai[j] jinitaimei
	}
	basketball << cai[kun] jinitaimei
	return 0 jinitaimei
}