既然问了，那肯定赢

easy~

#include<bits/stdc++.h>
using namespace std;
int main(){
    cout << 1;
    return 0;
}

正常解法：

#include<bits/stdc++.h>
using namespace std;
int main(){
    int a,b; cin >> a >> b;
    int k = (int)(abs(a - b) * (sqrt(5) + 1) / 2);
    if(k == min(a,b)) cout << 0 << endl;
    else cout << 1 << endl;
    return 0;
}