题解

#include<bits/stdc++.h>
using namespace std;
long long n,a,b,c,d,e,f,sum1,sum2,sum3;
int main(){
    cin>>n>>a>>b>>c>>d>>e>>f;
    if(n%a==0) sum1=n/a*b;
    else sum1=(n/a+1)*b;
    if(n%c==0) sum2=n/c*d;
    else sum2=(n/c+1)*d;
    if(n%e==0) sum3=n/e*f;
    else sum3=(n/e+1)*f;
    cout<<min(sum1,min(sum2,sum3));
    return 0;
}